Answer:


a. To compute for the population mean, we need to use the formula , then we have


 





 


b. For the population standard deviation, the formula  should be used, then we have:


 


X




7


1


1


5


-1


1


11


5


25


8


2


4


3


-3


9


6


0


0


2


-4


16


1


-5


25


9


3


9


8


2


4


60


 


=94


 





 


 


 


 


 


 


 



 

Answer:


a. To compute for the population mean, we need to use the formula , then we have


 





 


b. For the population standard deviation, the formula  should be used, then we have:


 


X




7


1


1


5


-1


1


6


0


0


6


0


0


6


0


0


4


-2


4


8


2


4


6


0


0


9


3


9


3


-3


9


60


 


=28


 





 


 


 


 


 


 


 


Answers:


a.


 


Five Number Summary


Values


median


7


25th percentile/Quartile 1


4.75


minimum


3


maximum


12


75th percentile/Quartile 3


8.5


 


b.



 


            From the figure, we may say that our data set is negatively skewed. As illustrated, the distance from the first quartile to the median (i.e. – 4.75\ = 2.25) is longer than the distance from the median to the third quartile (i.e. – 8.5\ = 1.5). Apparently, the discrepancy of the median to the center of the box is relatively small, then it is almost considered to be in normal distribution.


 


 


 


 


 


 


 


 



 

Answers:


 


a.


Five Number Summary


Values


median


7


25th percentile/Quartile 1


3.5


minimum


0


maximum


12


75th percentile/Quartile 3


8


 


b.



 


            From the given information and the details of the graph, it shows that the middle 50 percent of the data take between 3.5 and 8.  In accordance to skewness, the distribution is negatively skewed whereas the distance from the first quartile to the median (i.e. – 3.5\ = 3. 5) is longer than the distance from the median to the third quartile (i.e. – 8\ = 1).



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